sort list based on another list javasort list based on another list java

@Jack Yes, like what I did in the last example. Did any DOS compatibility layers exist for any UNIX-like systems before DOS started to become outmoded? Why is this sentence from The Great Gatsby grammatical? Working on improving health and education, reducing inequality, and spurring economic growth? That way, I can sort any list in the same order as the source list. more_itertools has a tool for sorting iterables in parallel: I actually came here looking to sort a list by a list where the values matched. http://scienceoss.com/sort-one-list-by-another-list/. Acidity of alcohols and basicity of amines. Something like this? The solution below is simple and does not require any imports. rev2023.3.3.43278. In addition, the proposed solution won't work for the initial question as the lists X and Y contain different entries. Making statements based on opinion; back them up with references or personal experience. Create a Map that maps the values of everything in listB to something that can be sorted easily, such as the index, i.e. What is the shortest way of sorting X using values from Y to get the following output? I want to sort listA based on listB. The second one is easier and faster if you're not using Pandas in your program. Let's define a User class, which isn't Comparable and see how we can sort them in a List, using Stream.sorted(): In the first iteration of this example, let's say we want to sort our users by their age. What am I doing wrong here in the PlotLegends specification? The common non-linear data structure known as a tree. This will provide a quick and easy lookup. Connect and share knowledge within a single location that is structured and easy to search. Otherwise, I see a lot of answers here using Collections.sort(), however there is an alternative method which is guaranteed O(2n) runtime, which should theoretically be faster than sort's worst time complexity of O(nlog(n)), at the cost of 2n storage. We can sort the entries in a HashMap according to keys as well as values. We will use a simple sorting algorithm, Bubble Sort, to sort the elements of a linked list in ascending order below. In case of Strings, they're sorted lexicographically: If we wanted the newly sorted list saved, the same procedure as with the integers applies here: Check out our hands-on, practical guide to learning Git, with best-practices, industry-accepted standards, and included cheat sheet. Can Martian regolith be easily melted with microwaves? The best answers are voted up and rise to the top, Not the answer you're looking for? Linear regulator thermal information missing in datasheet. http://scienceoss.com/sort-one-list-by-another-list/. Has 90% of ice around Antarctica disappeared in less than a decade? vegan) just to try it, does this inconvenience the caterers and staff? @Debacle: Please clarify two things: 1) Is there a 1:1 correspondance between listA and listB? The nature of simulating nature: A Q&A with IBM Quantum researcher Dr. Jamie We've added a "Necessary cookies only" option to the cookie consent popup, Sorting Each Entry (code review + optimization), Sorting linked list with comparator in Java, Sorting a list of numbers, each with a character label, Invoking thread for each item in list simultaneously and returning value in Java, Sort a Python list of strings where each item is made with letters and numbers. If the elements of the stream are not Comparable, a java.lang.ClassCastException may be thrown upon execution. From simple plot types to ridge plots, surface plots and spectrograms - understand your data and learn to draw conclusions from it. How can this new ban on drag possibly be considered constitutional? Replacing broken pins/legs on a DIP IC package. Your problem statement is not very clear. This trick will never fails and ensures the mapping between the items in list. C:[a,b,c]. This method will also work when both lists are not identical: Problem : sorting a list of Pojo on the basis of one of the field's all possible values present in another list. The solution below is simple and should fix those issues: Location of index in list2 is tracked using cur_loclist. You can use a Bean Comparator to sort this List however you desire. All rights reserved. If you already have a dfwhy converting it to a list, process it, then convert to df again? not if you call the sort after merging the list as suggested here. MathJax reference. So we pass User::getCreatedOn to sort by the createdOn field. unit tests. Sorting a 10000 items list 100 times improves speed 140 times (265 ms for the whole batch instead of 37 seconds) on my How can I pair socks from a pile efficiently? In this quick tutorial, we'll learn how to find items from one list based on values from another list using Java 8 Streams. To sort the String values in the list we use a comparator. rev2023.3.3.43278. Assume that the dictionary and the words only contain lowercase alphabets. To sort the String values in the list we use a comparator. Whereas, Integer values are directly sorted using Collection.sort(). I used java 8 streams to sort lists and put them in ArrayDeques. Take a look at this solution, may be this is what you are trying to achieve: O U T P U T What I am doing require to sort collection of factories and loop through all factories and sort collection of their competitors. It is defined in Stream interface which is present in java.util package. How do I generate random integers within a specific range in Java? An in-place sort is preferred whenever possible. I was in a rush. Most of the solutions above are complicated and I think they will not work if the lists are of different lengths or do not contain the exact same items. I have two lists List list1 = new ArrayList(), list2 = new ArrayList(); (Not the same size), of the class Person: I want to create a new list using list1 and list2 sorted by age (descending), but I also another condition that is better explained with an example: He should, because his age is equal to Menard, Alec is from L1 and two Person from L1 can't be one after another is this kind of situation happens. We can use the following methods to sort the list: Using stream.sorted () method Using Comparator.reverseOrder () method Using Comparator.naturalOrder () method Using Collections.reverseOrder () method Using Collections.sort () method Java Stream interface Java Stream interface provides two methods for sorting the list: sorted () method You posted your solution two times. Oh, ignore, I can do sorted(zip(Index,X,Y,Z)) too. Site design / logo 2023 Stack Exchange Inc; user contributions licensed under CC BY-SA. @Richard: the keys are computed once before sorting; so the complexity is actually O(N^2). When we compare null, it throws NullPointerException. Once we have the list of values in a sorted manner, we build the HashMap again based on this new list. If the age of the users is the same, the first one that was added to the list will be the first in the sorted order. Why do many companies reject expired SSL certificates as bugs in bug bounties? My lists are long enough to make the solutions with time complexity of N^2 unusable. Surly Straggler vs. other types of steel frames. The most obvious solution to me is to use the key keyword arg. In each iteration, follow the following step . Find centralized, trusted content and collaborate around the technologies you use most. L1-50 first, L2-50 next, then, L2-45, L2-42, L1-40 and L1-30. Overview Filtering a Collection by a List is a common business logic scenario. You can implement a custom Comparator to sort a list by multiple attributes. Theoretically Correct vs Practical Notation, Bulk update symbol size units from mm to map units in rule-based symbology. 3.1. Did you try it with the sample lists. Given parallel lists, how can I sort one while permuting (rearranging) the other in the same way? Does a summoned creature play immediately after being summoned by a ready action? JavaTpoint offers college campus training on Core Java, Advance Java, .Net, Android, Hadoop, PHP, Web Technology and Python. How to Sort a List by a property in the object. you can leverage that solution directly in your existing df. As for won't work..that's right because he posted the wrong question in the title when he talked about lists. If the data is related then the data should be stored together in a simple class. Mark should be before Robert, in a list sorted by name, but in the list we've sorted previously, it's the other way around. Styling contours by colour and by line thickness in QGIS. Speed improvement on JB Nizet's answer (from the suggestion he made himself). NULL). Check out our offerings for compute, storage, networking, and managed databases. 2. You can use this generic comparator to sort list based on the the other list. Given parallel lists, how can I sort one while permuting (rearranging) the other in the same way? You are using Python 3. good solution! 2. In this case, the key extractor could be the method reference Factory::getPrice (resp. Connect and share knowledge within a single location that is structured and easy to search. I want to create a new list using list1 and list2 sorted by age (descending), but I also another condition that is better explained with an example: . A example will show this. We've sorted Comparable integers and Strings, in ascending and descending order, as well as used a built-in Comparator for custom objects. String values require a comparator for sorting. Sorting HashMap by Value Simple Example. Here if the data type of Value is String, then we sort the list using a comparator. If you try your proposed code, it would give something like this: Person{name=Giant L2, age=100} Person{name=Derp L1, age=50} Person{name=John L2, age=50} Person{name=Menard L1, age=44} Person{name=Lili L1, age=44} Person{name=Lili L2, age=44} Person{name=Menard L2, age=44} Person{name=Bob L1, age=22} Person{name=Alec L1, age=21} Person{name=Herp L1, age=21} Person{name=Alec L2, age=21} Person{name=Herp L2, age=21} Person{name=Alice L1, age=12} Person{name=Little L2, age=5} And it's not what I'm looking for. Is it possible to create a concave light? So basically, I have 2 ArrayLists (listA and listB). 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I am a bit confused with FactoryPriceComparator class. Python. Linear regulator thermal information missing in datasheet, Short story taking place on a toroidal planet or moon involving flying, Identify those arcade games from a 1983 Brazilian music video, It is also probably wrong to have your class implements. Sometimes, you might want to switch this up and sort in descending order. The signature of the method is: T: Comparable type of element to be compared. Disconnect between goals and daily tasksIs it me, or the industry? Sorting a 10000 items list 100 times improves speed 140 times (265 ms for the whole batch instead of 37 seconds) on my unit tests. In Java there are set of classes which can be useful to sort lists or arrays. 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Edit: Fixed this line return this.left.compareTo(o.left);. There are at least two good idioms for this problem. Starting with the example input you provided: This is also known as the Schwartzian_transform after R. Schwartz who popularized this pattern in Perl in the 90s: Note that in this case Y and X are sorted and compared lexicographically. Lets look at an example where our value is a custom object. Can I tell police to wait and call a lawyer when served with a search warrant? Is there a single-word adjective for "having exceptionally strong moral principles"? Given an array of strings words [] and the sequential order of alphabets, our task is to sort the array according to the order given. Find the max recommended item from second sublist (3 to end of list) and add it to the newly created list and . As each pair of strings are passed in for comparison, convert them into ints using originalList.indexOf, except that if the index is -1, change the index to originalList.size () Compare the two ints. If changes are possible, you would need to somehow listen for changes to the original list and update the indices inside the custom list. The second issue is that if listA and listB do contain references to the same objects (which makes the first issue moot, of course), and they contain the same objects (as the OP implied when he said "reordered"), then this whole thing is the same as, And a third major issue is that by the end of this function you're left with some pretty weird side effects. More general case (sort list Y by any key instead of the default order), http://scienceoss.com/sort-one-list-by-another-list/, How Intuit democratizes AI development across teams through reusability. @Hatefiend interesting, could you point to a reference on how to achieve that? . Originally posted by David O'Meara: Then when you initialise your Comparator, pass in the list used for ordering. Are there tables of wastage rates for different fruit and veg? How to make it come last.? Why is this sentence from The Great Gatsby grammatical? To learn more, see our tips on writing great answers. We can sort a list in natural ordering where the list elements must implement Comparable interface. The nature of simulating nature: A Q&A with IBM Quantum researcher Dr. Jamie We've added a "Necessary cookies only" option to the cookie consent popup, The most efficient way to merge two lists in Java, Java merge sort implementation efficiency. The source of these elements is usually a Collection or an Array, from which data is provided to the stream. How To Install Grails on an Ubuntu 12.04 VPS, Simple and reliable cloud website hosting, New! I can resort to the use of for constructs but I am curious if there is a shorter way. Note: Any item not in list1 will be ignored since the algorithm will not know what's the sort order to use. Returning a negative number indicates that an element is lesser than another. @Richard: the keys are computed once before sorting; so the complexity is actually O(N^2). I used java 8 streams to sort lists and put them in ArrayDeques. What is the shortest way of sorting X using values from Y to get the following output? This is an old question but some of the answers I see posted don't actually work because zip is not scriptable. Note that the class must implement Comparable interface. Application of Binary Tree. See JB Nizet's answer for an example of a custom Comparator that does this. Learn more. In this tutorial, we will learn how to sort a list in the natural order. If the elements are not comparable, it throws java.lang.ClassCastException. On the Data tab of the Ribbon, in the Sort & Filter group, click Advanced.
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